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	<title>Comments on: sqrt(16) &#8211; how many answers?</title>
	<atom:link href="http://www.squarecirclez.com/blog/16-how-many-answers/122/feed" rel="self" type="application/rss+xml" />
	<link>http://www.squarecirclez.com/blog/16-how-many-answers/122</link>
	<description>Mathematics, learning, computing, travel - and whatever...</description>
	<lastBuildDate>Sun, 12 Feb 2012 08:08:30 +0000</lastBuildDate>
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		<title>By: Murray</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-333327</link>
		<dc:creator>Murray</dc:creator>
		<pubDate>Thu, 18 Nov 2010 06:42:43 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-333327</guid>
		<description>Hi Tammy. Yes, most of the time the square root sign is taken to mean the &quot;principal&quot; square root (that is, the positive case only).

And that&#039;s my point.

In a follow-up post I give the &lt;a href=&quot;http://www.squarecirclez.com/blog/square-root-how-many/133&quot; rel=&quot;nofollow&quot;&gt;Oxford Concise Dictionary of Mathematics definition of square root&lt;/a&gt;.</description>
		<content:encoded><![CDATA[<p>Hi Tammy. Yes, most of the time the square root sign is taken to mean the &#8220;principal&#8221; square root (that is, the positive case only).</p>
<p>And that&#8217;s my point.</p>
<p>In a follow-up post I give the <a href="http://www.squarecirclez.com/blog/square-root-how-many/133" rel="nofollow">Oxford Concise Dictionary of Mathematics definition of square root</a>.</p>
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		<title>By: Tammy</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-333281</link>
		<dc:creator>Tammy</dc:creator>
		<pubDate>Wed, 17 Nov 2010 18:01:21 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-333281</guid>
		<description>http://www.mathsisfun.com/algebra/square-root.html

If you scroll about halfway down to the section labeled Principal Square Root, there is an easy-to-understand (to me, anyway) explanation about the fact that a number has both a negative and a positive square root, but the positive one is the Principal Square Root.  There is even a graph of an equation showing why this must be the case. 

Thoughts?</description>
		<content:encoded><![CDATA[<p><a href="http://www.mathsisfun.com/algebra/square-root.html" rel="nofollow">http://www.mathsisfun.com/algebra/square-root.html</a></p>
<p>If you scroll about halfway down to the section labeled Principal Square Root, there is an easy-to-understand (to me, anyway) explanation about the fact that a number has both a negative and a positive square root, but the positive one is the Principal Square Root.  There is even a graph of an equation showing why this must be the case. </p>
<p>Thoughts?</p>
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		<title>By: Khurram</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-165544</link>
		<dc:creator>Khurram</dc:creator>
		<pubDate>Tue, 01 Dec 2009 15:25:26 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-165544</guid>
		<description>there is a difference between x^2 = 16 and x = &#8730;16
as when we add a root in a question by ourselves than and than only will the answer be ± .If it is given already in the question that x equals to the root of something than the answer will only be the positive one</description>
		<content:encoded><![CDATA[<p>there is a difference between x^2 = 16 and x = &radic;16<br />
as when we add a root in a question by ourselves than and than only will the answer be ± .If it is given already in the question that x equals to the root of something than the answer will only be the positive one</p>
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		<title>By: Nabin K. Neupane</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-100410</link>
		<dc:creator>Nabin K. Neupane</dc:creator>
		<pubDate>Sun, 09 Aug 2009 14:45:10 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-100410</guid>
		<description>Thanks for the answer. I agree with u</description>
		<content:encoded><![CDATA[<p>Thanks for the answer. I agree with u</p>
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		<title>By: Murray</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-95491</link>
		<dc:creator>Murray</dc:creator>
		<pubDate>Sat, 18 Jul 2009 11:48:26 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-95491</guid>
		<description>Thanks John for your input - and great to hear from you!</description>
		<content:encoded><![CDATA[<p>Thanks John for your input &#8211; and great to hear from you!</p>
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		<title>By: John</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-95381</link>
		<dc:creator>John</dc:creator>
		<pubDate>Fri, 17 Jul 2009 17:28:07 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-95381</guid>
		<description>Murray is correct.  &#8730;16 = 4 , not &#177;4.  If the latter were true, then the quadratic formula would not need a &#177; symbol in it.

Furthermore, the definition of the absolute value function is

&#124;x&#124;=&#8730;(x^2)

This would not work were &#8730;(x^2)=&#177;x</description>
		<content:encoded><![CDATA[<p>Murray is correct.  &radic;16 = 4 , not &plusmn;4.  If the latter were true, then the quadratic formula would not need a &plusmn; symbol in it.</p>
<p>Furthermore, the definition of the absolute value function is</p>
<p>|x|=&radic;(x^2)</p>
<p>This would not work were &radic;(x^2)=&plusmn;x</p>
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		<title>By: favor</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-90484</link>
		<dc:creator>favor</dc:creator>
		<pubDate>Fri, 26 Jun 2009 21:25:18 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-90484</guid>
		<description>yes, that&#039;s true. 
the first equation has two solutions ±&#8730;16  which are +4 and -4, but in the second one, the solution is already limited to just one of the two which is +&#8730;16 = +4. Period</description>
		<content:encoded><![CDATA[<p>yes, that&#8217;s true.<br />
the first equation has two solutions ±&radic;16  which are +4 and -4, but in the second one, the solution is already limited to just one of the two which is +&radic;16 = +4. Period</p>
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		<title>By: Qlumbo</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-71925</link>
		<dc:creator>Qlumbo</dc:creator>
		<pubDate>Wed, 01 Apr 2009 19:11:46 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-71925</guid>
		<description>Ah. Thanks for the answer. Good point.</description>
		<content:encoded><![CDATA[<p>Ah. Thanks for the answer. Good point.</p>
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		<title>By: Murray</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-67577</link>
		<dc:creator>Murray</dc:creator>
		<pubDate>Fri, 06 Mar 2009 01:01:50 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-67577</guid>
		<description>In my post, I did not use the words &quot;square root&quot;. I used the radical symbol, &#8730;.

I agree with the &lt;a href=&quot;http://en.wikipedia.org/wiki/Square_root&quot; rel=&quot;nofollow&quot;&gt;Wikipedia author who wrote&lt;/a&gt;:

&lt;blockquote&gt;Every positive number x has two square roots. One of them is &#8730;&lt;i&gt;x&lt;/i&gt;, which is positive, and the other &#8722;&#8730;&lt;i&gt;x&lt;/i&gt;, which is negative.&lt;/blockquote&gt;

This is a notation issue, as well as a semantic one.</description>
		<content:encoded><![CDATA[<p>In my post, I did not use the words &#8220;square root&#8221;. I used the radical symbol, &radic;.</p>
<p>I agree with the <a href="http://en.wikipedia.org/wiki/Square_root" rel="nofollow">Wikipedia author who wrote</a>:</p>
<blockquote><p>Every positive number x has two square roots. One of them is &radic;<i>x</i>, which is positive, and the other &minus;&radic;<i>x</i>, which is negative.</p></blockquote>
<p>This is a notation issue, as well as a semantic one.</p>
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		<title>By: Qlumbo</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-67558</link>
		<dc:creator>Qlumbo</dc:creator>
		<pubDate>Thu, 05 Mar 2009 22:39:22 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-67558</guid>
		<description>Hmm...that&#039;s weird. Getting a solid definition of square root would entirely answer the question though.

We should also remember that square root is not some super-special operation...you&#039;re just taking the exponent of 0.5. 

I&#039;m starting to wonder about the cube root of 8. Cube rooting isn&#039;t special either and belongs in the same group with any other exponent, but just since it isn&#039;t divisible by 2 we come out with one answer without argument.

Definition of square root:
    A number that when multiplied by itself equals a given
    number.
-4, when multiplied by itself gives 16 and so does 4. And once again, there is nothing wrong with having 2 answers.
Is there anything against this?</description>
		<content:encoded><![CDATA[<p>Hmm&#8230;that&#8217;s weird. Getting a solid definition of square root would entirely answer the question though.</p>
<p>We should also remember that square root is not some super-special operation&#8230;you&#8217;re just taking the exponent of 0.5. </p>
<p>I&#8217;m starting to wonder about the cube root of 8. Cube rooting isn&#8217;t special either and belongs in the same group with any other exponent, but just since it isn&#8217;t divisible by 2 we come out with one answer without argument.</p>
<p>Definition of square root:<br />
    A number that when multiplied by itself equals a given<br />
    number.<br />
-4, when multiplied by itself gives 16 and so does 4. And once again, there is nothing wrong with having 2 answers.<br />
Is there anything against this?</p>
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