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	<title>Comments on: sqrt(16) &#8211; how many answers?</title>
	<atom:link href="http://www.squarecirclez.com/blog/16-how-many-answers/122/feed" rel="self" type="application/rss+xml" />
	<link>http://www.squarecirclez.com/blog/16-how-many-answers/122</link>
	<description>Mathematics, learning, computing, travel - and whatever...</description>
	<lastBuildDate>Tue, 16 Mar 2010 02:48:59 +0000</lastBuildDate>
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		<title>By: Khurram</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-165544</link>
		<dc:creator>Khurram</dc:creator>
		<pubDate>Tue, 01 Dec 2009 15:25:26 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-165544</guid>
		<description>there is a difference between x^2 = 16 and x = &#8730;16
as when we add a root in a question by ourselves than and than only will the answer be ± .If it is given already in the question that x equals to the root of something than the answer will only be the positive one</description>
		<content:encoded><![CDATA[<p>there is a difference between x^2 = 16 and x = &radic;16<br />
as when we add a root in a question by ourselves than and than only will the answer be ± .If it is given already in the question that x equals to the root of something than the answer will only be the positive one</p>
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		<title>By: Nabin K. Neupane</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-100410</link>
		<dc:creator>Nabin K. Neupane</dc:creator>
		<pubDate>Sun, 09 Aug 2009 14:45:10 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-100410</guid>
		<description>Thanks for the answer. I agree with u</description>
		<content:encoded><![CDATA[<p>Thanks for the answer. I agree with u</p>
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		<title>By: zac</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-95491</link>
		<dc:creator>zac</dc:creator>
		<pubDate>Sat, 18 Jul 2009 11:48:26 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-95491</guid>
		<description>Thanks John for your input - and great to hear from you!</description>
		<content:encoded><![CDATA[<p>Thanks John for your input &#8211; and great to hear from you!</p>
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		<title>By: John</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-95381</link>
		<dc:creator>John</dc:creator>
		<pubDate>Fri, 17 Jul 2009 17:28:07 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-95381</guid>
		<description>Murray is correct.  &#8730;16 = 4 , not &#177;4.  If the latter were true, then the quadratic formula would not need a &#177; symbol in it.

Furthermore, the definition of the absolute value function is

&#124;x&#124;=&#8730;(x^2)

This would not work were &#8730;(x^2)=&#177;x</description>
		<content:encoded><![CDATA[<p>Murray is correct.  &radic;16 = 4 , not &plusmn;4.  If the latter were true, then the quadratic formula would not need a &plusmn; symbol in it.</p>
<p>Furthermore, the definition of the absolute value function is</p>
<p>|x|=&radic;(x^2)</p>
<p>This would not work were &radic;(x^2)=&plusmn;x</p>
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		<title>By: favor</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-90484</link>
		<dc:creator>favor</dc:creator>
		<pubDate>Fri, 26 Jun 2009 21:25:18 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-90484</guid>
		<description>yes, that&#039;s true. 
the first equation has two solutions ±&#8730;16  which are +4 and -4, but in the second one, the solution is already limited to just one of the two which is +&#8730;16 = +4. Period</description>
		<content:encoded><![CDATA[<p>yes, that&#8217;s true.<br />
the first equation has two solutions ±&radic;16  which are +4 and -4, but in the second one, the solution is already limited to just one of the two which is +&radic;16 = +4. Period</p>
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		<title>By: Qlumbo</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-71925</link>
		<dc:creator>Qlumbo</dc:creator>
		<pubDate>Wed, 01 Apr 2009 19:11:46 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-71925</guid>
		<description>Ah. Thanks for the answer. Good point.</description>
		<content:encoded><![CDATA[<p>Ah. Thanks for the answer. Good point.</p>
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		<title>By: zac</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-67577</link>
		<dc:creator>zac</dc:creator>
		<pubDate>Fri, 06 Mar 2009 01:01:50 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-67577</guid>
		<description>In my post, I did not use the words &quot;square root&quot;. I used the radical symbol, &#8730;.

I agree with the &lt;a href=&quot;http://en.wikipedia.org/wiki/Square_root&quot; rel=&quot;nofollow&quot;&gt;Wikipedia author who wrote&lt;/a&gt;:

&lt;blockquote&gt;Every positive number x has two square roots. One of them is &#8730;&lt;i&gt;x&lt;/i&gt;, which is positive, and the other &#8722;&#8730;&lt;i&gt;x&lt;/i&gt;, which is negative.&lt;/blockquote&gt;

This is a notation issue, as well as a semantic one.</description>
		<content:encoded><![CDATA[<p>In my post, I did not use the words &#8220;square root&#8221;. I used the radical symbol, &radic;.</p>
<p>I agree with the <a href="http://en.wikipedia.org/wiki/Square_root" rel="nofollow">Wikipedia author who wrote</a>:</p>
<blockquote><p>Every positive number x has two square roots. One of them is &radic;<i>x</i>, which is positive, and the other &minus;&radic;<i>x</i>, which is negative.</p></blockquote>
<p>This is a notation issue, as well as a semantic one.</p>
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		<title>By: Qlumbo</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-67558</link>
		<dc:creator>Qlumbo</dc:creator>
		<pubDate>Thu, 05 Mar 2009 22:39:22 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-67558</guid>
		<description>Hmm...that&#039;s weird. Getting a solid definition of square root would entirely answer the question though.

We should also remember that square root is not some super-special operation...you&#039;re just taking the exponent of 0.5. 

I&#039;m starting to wonder about the cube root of 8. Cube rooting isn&#039;t special either and belongs in the same group with any other exponent, but just since it isn&#039;t divisible by 2 we come out with one answer without argument.

Definition of square root:
    A number that when multiplied by itself equals a given
    number.
-4, when multiplied by itself gives 16 and so does 4. And once again, there is nothing wrong with having 2 answers.
Is there anything against this?</description>
		<content:encoded><![CDATA[<p>Hmm&#8230;that&#8217;s weird. Getting a solid definition of square root would entirely answer the question though.</p>
<p>We should also remember that square root is not some super-special operation&#8230;you&#8217;re just taking the exponent of 0.5. </p>
<p>I&#8217;m starting to wonder about the cube root of 8. Cube rooting isn&#8217;t special either and belongs in the same group with any other exponent, but just since it isn&#8217;t divisible by 2 we come out with one answer without argument.</p>
<p>Definition of square root:<br />
    A number that when multiplied by itself equals a given<br />
    number.<br />
-4, when multiplied by itself gives 16 and so does 4. And once again, there is nothing wrong with having 2 answers.<br />
Is there anything against this?</p>
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		<title>By: johnson ojofu</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-66426</link>
		<dc:creator>johnson ojofu</dc:creator>
		<pubDate>Mon, 23 Feb 2009 21:13:41 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-66426</guid>
		<description>hi
as for me i strongly believe that the answer is four, because when u take the square to the other side, it then becomes square sixteen. therefore the square root of sixteen is four</description>
		<content:encoded><![CDATA[<p>hi<br />
as for me i strongly believe that the answer is four, because when u take the square to the other side, it then becomes square sixteen. therefore the square root of sixteen is four</p>
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		<title>By: zac</title>
		<link>http://www.squarecirclez.com/blog/16-how-many-answers/122/comment-page-1#comment-52652</link>
		<dc:creator>zac</dc:creator>
		<pubDate>Fri, 14 Nov 2008 23:59:24 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/16-how-many-answers/122#comment-52652</guid>
		<description>Thanks for your opinion, Qlumbo.

&lt;i&gt;I am not sure what happens if you are programming and you use the sqrt() function...&lt;/i&gt;

You get one positive answer, as it should be.

&lt;i&gt;I am not sure what happens with maybe other calculators...&lt;/i&gt;

All calculators give you one positive answer, as they should.

There&#039;s another example where it is assumed (correctly) that the square root symbol, &#8730;, gives a positive answer only.

The &lt;a href=&quot;http://www.intmath.com/Quadratic-equations/3_Quadratic-formula.php&quot; rel=&quot;nofollow&quot;&gt;quadratic equation&lt;/a&gt;, which everyone manages to learn sometime in their math career, says:

The solution for &lt;i&gt;ax&lt;/i&gt;&lt;sup&gt;2&lt;/sup&gt; + &lt;i&gt;bx + c&lt;/i&gt; = 0 is

&lt;i&gt;x&lt;/i&gt; = [-&lt;i&gt;b&lt;/i&gt; &#177; &#8730;(&lt;i&gt;b&lt;/i&gt;&lt;sup&gt;2&lt;/sup&gt; - 4&lt;i&gt;ac&lt;/i&gt;)]/2&lt;i&gt;a&lt;/i&gt;

If the &#8730; sign meant plus &lt;b&gt;and&lt;/b&gt; minus, why then why would we need the &#177; sign in the formula?

&#8730;16 is 4, only.</description>
		<content:encoded><![CDATA[<p>Thanks for your opinion, Qlumbo.</p>
<p><i>I am not sure what happens if you are programming and you use the sqrt() function&#8230;</i></p>
<p>You get one positive answer, as it should be.</p>
<p><i>I am not sure what happens with maybe other calculators&#8230;</i></p>
<p>All calculators give you one positive answer, as they should.</p>
<p>There&#8217;s another example where it is assumed (correctly) that the square root symbol, &radic;, gives a positive answer only.</p>
<p>The <a href="http://www.intmath.com/Quadratic-equations/3_Quadratic-formula.php" rel="nofollow">quadratic equation</a>, which everyone manages to learn sometime in their math career, says:</p>
<p>The solution for <i>ax</i><sup>2</sup> + <i>bx + c</i> = 0 is</p>
<p><i>x</i> = [-<i>b</i> &plusmn; &radic;(<i>b</i><sup>2</sup> - 4<i>ac</i>)]/2<i>a</i></p>
<p>If the &radic; sign meant plus <b>and</b> minus, why then why would we need the &plusmn; sign in the formula?</p>
<p>&radic;16 is 4, only.</p>
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