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	<title>Comments on: Impossible questions continue</title>
	<atom:link href="http://www.squarecirclez.com/blog/impossible-questions-continue/320/feed" rel="self" type="application/rss+xml" />
	<link>http://www.squarecirclez.com/blog/impossible-questions-continue/320</link>
	<description>Mathematics, learning, computing, travel - and whatever...</description>
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		<title>By: MariaD</title>
		<link>http://www.squarecirclez.com/blog/impossible-questions-continue/320/comment-page-1#comment-61361</link>
		<dc:creator>MariaD</dc:creator>
		<pubDate>Sat, 17 Jan 2009 12:30:23 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/impossible-questions-continue/320#comment-61361</guid>
		<description>Of course, there is always the classic: &lt;a href=&quot;http://www.naturalmath.com/lolmath/view-31.html&quot; rel=&quot;nofollow&quot;&gt;LOLMath&lt;/a&gt;</description>
		<content:encoded><![CDATA[<p>Of course, there is always the classic: <a href="http://www.naturalmath.com/lolmath/view-31.html" rel="nofollow">LOLMath</a></p>
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		<title>By: zac</title>
		<link>http://www.squarecirclez.com/blog/impossible-questions-continue/320/comment-page-1#comment-61342</link>
		<dc:creator>zac</dc:creator>
		<pubDate>Sat, 17 Jan 2009 10:05:57 +0000</pubDate>
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		<description>Hi Maria and good to hear from you.

You&#039;ve reminded me of the collection that I have somewhere. It includes all the howlers that students have written in assignments and exams. Now, where did I put it...?</description>
		<content:encoded><![CDATA[<p>Hi Maria and good to hear from you.</p>
<p>You&#8217;ve reminded me of the collection that I have somewhere. It includes all the howlers that students have written in assignments and exams. Now, where did I put it&#8230;?</p>
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		<title>By: MariaD</title>
		<link>http://www.squarecirclez.com/blog/impossible-questions-continue/320/comment-page-1#comment-60508</link>
		<dc:creator>MariaD</dc:creator>
		<pubDate>Sun, 11 Jan 2009 13:19:22 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/impossible-questions-continue/320#comment-60508</guid>
		<description>My favorite, from my math site &quot;Contact us&quot; form, was a one-liner with no name, no return address, no capitalization, no nothing. It read, simply:

help me

I have a collection called &quot;Messages from the universe&quot; and that&#039;s where it went. I think I&#039;ve been answering it, to the best of my abilities.</description>
		<content:encoded><![CDATA[<p>My favorite, from my math site &#8220;Contact us&#8221; form, was a one-liner with no name, no return address, no capitalization, no nothing. It read, simply:</p>
<p>help me</p>
<p>I have a collection called &#8220;Messages from the universe&#8221; and that&#8217;s where it went. I think I&#8217;ve been answering it, to the best of my abilities.</p>
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		<title>By: arron</title>
		<link>http://www.squarecirclez.com/blog/impossible-questions-continue/320/comment-page-1#comment-12523</link>
		<dc:creator>arron</dc:creator>
		<pubDate>Wed, 03 Oct 2007 21:25:17 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/impossible-questions-continue/320#comment-12523</guid>
		<description>if you think your so clever then answer this question

Let f be the function given by f(x)= e^(-2x^2) (read as e raised to the negative 2 x squared)

(a) Find the first four nonzero terms and the general term of the power seriews for f(x) about x=0.

(b) Find the interval of convergence of the power seriews for f(x) about x = 0. Show the analysis that leads to your conclusion.

(c) Let g be the function given by the sum of the first four nonzero terms of the power seriews for f(x) about x=0. Show that l f(x) - g(x) l </description>
		<content:encoded><![CDATA[<p>if you think your so clever then answer this question</p>
<p>Let f be the function given by f(x)= e^(-2x^2) (read as e raised to the negative 2 x squared)</p>
<p>(a) Find the first four nonzero terms and the general term of the power seriews for f(x) about x=0.</p>
<p>(b) Find the interval of convergence of the power seriews for f(x) about x = 0. Show the analysis that leads to your conclusion.</p>
<p>(c) Let g be the function given by the sum of the first four nonzero terms of the power seriews for f(x) about x=0. Show that l f(x) &#8211; g(x) l</p>
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		<title>By: zac</title>
		<link>http://www.squarecirclez.com/blog/impossible-questions-continue/320/comment-page-1#comment-12524</link>
		<dc:creator>zac</dc:creator>
		<pubDate>Wed, 03 Oct 2007 16:22:34 +0000</pubDate>
		<guid isPermaLink="false">http://www.squarecirclez.com/blog/impossible-questions-continue/320#comment-12524</guid>
		<description>Hi Arron and thank you for your question. 

I&#039;m sorry if my post came across as arrogant to you. My point was that many students have problems &lt;b&gt;asking&lt;/b&gt; questions properly, because in most classrooms, they are told to be quiet and listen. If teachers encouraged more discussion, then students would have more question asking skills, making it easier for others to understand where the problem lies.

I would use the &lt;a href=&quot;http://www.intmath.com/Series-expansion/2_Maclaurin-series.php&quot; rel=&quot;nofollow&quot;&gt;Mclaurin Series&lt;/a&gt; expansion of the function for part (a), giving 1 &#8722; 2x&lt;sup&gt;2&lt;/sup&gt; + 2x&lt;sup&gt;4&lt;/sup&gt; &#8722;  (4/3)x&lt;sup&gt;6&lt;/sup&gt; + ...

For (b), I would use &lt;a href=&quot;http://www.sosmath.com/calculus/radcon/radcon02/radcon02.html&quot; rel=&quot;nofollow&quot;&gt;this process&lt;/a&gt;.

Question (c) is incomplete.</description>
		<content:encoded><![CDATA[<p>Hi Arron and thank you for your question. </p>
<p>I&#8217;m sorry if my post came across as arrogant to you. My point was that many students have problems <b>asking</b> questions properly, because in most classrooms, they are told to be quiet and listen. If teachers encouraged more discussion, then students would have more question asking skills, making it easier for others to understand where the problem lies.</p>
<p>I would use the <a href="http://www.intmath.com/Series-expansion/2_Maclaurin-series.php" rel="nofollow">Mclaurin Series</a> expansion of the function for part (a), giving 1 &minus; 2x<sup>2</sup> + 2x<sup>4</sup> &minus;  (4/3)x<sup>6</sup> + &#8230;</p>
<p>For (b), I would use <a href="http://www.sosmath.com/calculus/radcon/radcon02/radcon02.html" rel="nofollow">this process</a>.</p>
<p>Question (c) is incomplete.</p>
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